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30x+18=-5x^2
We move all terms to the left:
30x+18-(-5x^2)=0
We get rid of parentheses
5x^2+30x+18=0
a = 5; b = 30; c = +18;
Δ = b2-4ac
Δ = 302-4·5·18
Δ = 540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{540}=\sqrt{36*15}=\sqrt{36}*\sqrt{15}=6\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6\sqrt{15}}{2*5}=\frac{-30-6\sqrt{15}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6\sqrt{15}}{2*5}=\frac{-30+6\sqrt{15}}{10} $
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